2(a+5)=6[a-(4-a)]

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Solution for 2(a+5)=6[a-(4-a)] equation:


Simplifying
2(a + 5) = 6[a + -1(4 + -1a)]

Reorder the terms:
2(5 + a) = 6[a + -1(4 + -1a)]
(5 * 2 + a * 2) = 6[a + -1(4 + -1a)]
(10 + 2a) = 6[a + -1(4 + -1a)]
10 + 2a = 6[a + (4 * -1 + -1a * -1)]
10 + 2a = 6[a + (-4 + 1a)]

Reorder the terms:
10 + 2a = 6[-4 + a + 1a]

Combine like terms: a + 1a = 2a
10 + 2a = 6[-4 + 2a]
10 + 2a = [-4 * 6 + 2a * 6]
10 + 2a = [-24 + 12a]

Solving
10 + 2a = -24 + 12a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-12a' to each side of the equation.
10 + 2a + -12a = -24 + 12a + -12a

Combine like terms: 2a + -12a = -10a
10 + -10a = -24 + 12a + -12a

Combine like terms: 12a + -12a = 0
10 + -10a = -24 + 0
10 + -10a = -24

Add '-10' to each side of the equation.
10 + -10 + -10a = -24 + -10

Combine like terms: 10 + -10 = 0
0 + -10a = -24 + -10
-10a = -24 + -10

Combine like terms: -24 + -10 = -34
-10a = -34

Divide each side by '-10'.
a = 3.4

Simplifying
a = 3.4

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